You should rearrange the elements of nums such that the modified array follows the given conditions:

1. Every consecutive pair of integers have opposite signs.
2. For all integers with the same sign, the order in which they were present in nums is preserved.
3. The rearranged array begins with a positive integer.

Return the modified array after rearranging the elements to satisfy the aforementioned conditions.

Example 1:

Input: nums = [3,1,-2,-5,2,-4]
Output: [3,-2,1,-5,2,-4]
Explanation:
The positive integers in nums are [3,1,2]. The negative integers are [-2,-5,-4].
The only possible way to rearrange them such that they satisfy all conditions is [3,-2,1,-5,2,-4].
Other ways such as [1,-2,2,-5,3,-4], [3,1,2,-2,-5,-4], [-2,3,-5,1,-4,2] are incorrect because they do not satisfy one or more conditions.  

Example 2:

Input: nums = [-1,1]
Output: [1,-1]
Explanation:
1 is the only positive integer and -1 the only negative integer in nums.
So nums is rearranged to [1,-1].

Constraints:

• 2 <= nums.length <= 2 * 105
• nums.length is even
• 1 <= |nums[i]| <= 105
• nums consists of equal number of positive and negative integers.

Solution 1: Split and merge

Create two arrays to store positive and negative numbers.

Time complexity: O(n)
Space complexity: O(n)

// Author: Huahua
class Solution {
public:
  vector<int> rearrangeArray(vector<int>& nums) {
    vector<int> pos;
    vector<int> neg;
    for (int x : nums)
      (x > 0 ? pos : neg).push_back(x);
    vector<int> ans;
    for (int i = 0; i < pos.size(); ++i) {
      ans.push_back(pos[i]);
      ans.push_back(neg[i]);
    }
    return ans;
  }
};

Solution 2: Two Pointers

Use two pointers to store the next pos / neg.

Time complexity: O(n)
Space complexity: O(n)

// Author: Huahua
class Solution {
public:
  vector<int> rearrangeArray(vector<int>& nums) {
    vector<int> ans(nums.size());    
    int pos = 0;
    int neg = 1;
    for (int x : nums) {
      int& index = x > 0 ? pos : neg;
      ans[index] = x;
      index += 2;
    }
    return ans;
  }
};

The post 花花酱 LeetCode 2149. Rearrange Array Elements by Sign appeared first on Huahua's Tech Road.