• 1 if x is positive.
• -1 if x is negative.
• 0 if x is equal to 0.

You are given an integer array nums. Let product be the product of all values in the array nums.

Return signFunc(product).

Example 1:

Input: nums = [-1,-2,-3,-4,3,2,1]
Output: 1
Explanation: The product of all values in the array is 144, and signFunc(144) = 1

Example 2:

Input: nums = [1,5,0,2,-3]
Output: 0
Explanation: The product of all values in the array is 0, and signFunc(0) = 0

Example 3:

Input: nums = [-1,1,-1,1,-1]
Output: -1
Explanation: The product of all values in the array is -1, and signFunc(-1) = -1

Constraints:

• 1 <= nums.length <= 1000
• -100 <= nums[i] <= 100

Solution: Sign Only

No need to compute the product, only track the sign changes. Flip the sign when encounter a negative number, return 0 if there is any 0 in the array.

Time complexity: O(n)
Space complexity: O(1)

// Author: Huahua
class Solution {
public:
  int arraySign(vector<int>& nums) {
    int sign = 1;
    for (int x : nums) {
      if (x == 0) return 0;
      else if (x < 0) sign = -sign;
    }
    return sign;
  }
};

The post 花花酱 LeetCode 1822. Sign of the Product of an Array appeared first on Huahua's Tech Road.