{"id":7856,"date":"2020-12-27T00:17:51","date_gmt":"2020-12-27T08:17:51","guid":{"rendered":"https:\/\/zxi.mytechroad.com\/blog\/?p=7856"},"modified":"2020-12-27T00:21:02","modified_gmt":"2020-12-27T08:21:02","slug":"leetcode-1704-determine-if-string-halves-are-alike","status":"publish","type":"post","link":"https:\/\/zxi.mytechroad.com\/blog\/string\/leetcode-1704-determine-if-string-halves-are-alike\/","title":{"rendered":"\u82b1\u82b1\u9171 LeetCode 1704. Determine if String Halves Are Alike"},"content":{"rendered":"\n

You are given a string s<\/code> of even length. Split this string into two halves of equal lengths, and let a<\/code> be the first half and b<\/code> be the second half.<\/p>\n\n\n\n

Two strings are alike<\/strong> if they have the same number of vowels ('a'<\/code>, 'e'<\/code>, 'i'<\/code>, 'o'<\/code>, 'u'<\/code>, 'A'<\/code>, 'E'<\/code>, 'I'<\/code>, 'O'<\/code>, 'U'<\/code>). Notice that s<\/code> contains uppercase and lowercase letters.<\/p>\n\n\n\n

Return true<\/code> if <\/em>a<\/code> and <\/em>b<\/code> are alike<\/strong><\/em>. Otherwise, return false<\/code>.<\/p>\n\n\n\n

Example 1:<\/strong><\/p>\n\n\n\n

Input:<\/strong> s = \"book\"\nOutput:<\/strong> true\nExplanation:<\/strong> a = \"bo\" and b = \"ok\". a has 1 vowel and b has 1 vowel. Therefore, they are alike.\n<\/pre>\n\n\n\n
Example 2:<\/strong><\/p>\n\n\n\n
Input:<\/strong> s = \"textbook\"\nOutput:<\/strong> false\nExplanation:<\/strong> a = \"text\" and b = \"book\". a has 1 vowel whereas b has 2. Therefore, they are not alike.\nNotice that the vowel o is counted twice.\n<\/pre>\n\n\n\n
Example 3:<\/strong><\/p>\n\n\n\n
Input:<\/strong> s = \"MerryChristmas\"\nOutput:<\/strong> false\n<\/pre>\n\n\n\n
Example 4:<\/strong><\/p>\n\n\n\n
Input:<\/strong> s = \"AbCdEfGh\"\nOutput:<\/strong> true\n<\/pre>\n\n\n\n
Constraints:<\/strong><\/p>\n\n\n\n
  • 2 <= s.length <= 1000<\/code><\/li>
  • s.length<\/code> is even.<\/li>
  • s<\/code> consists of uppercase and lowercase<\/strong> letters.<\/li><\/ul>\n\n\n\n
    Solution: Counting<\/strong><\/h2>\n\n\n\n
    Time complexity: O(n)
    Space complexity: O(1)<\/p>\n\n\n\n
    \n
    Python3<\/h2>\n
    \n\n
    # Author: Huahua\nclass Solution:\n  def halvesAreAlike(self, s: str) -> bool:\n    def count(s: str) -> int:\n      return sum(c in 'aeiouAEIOU' for c in s)\n    n = len(s)\n    return count(s[:n\/\/2]) == count(s[n\/\/2:])\n<\/pre>\n<\/div><\/div>\n","protected":false},"excerpt":{"rendered":"
    You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.…<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[47],"tags":[8,222,4,449],"class_list":["post-7856","post","type-post","status-publish","format-standard","hentry","category-string","tag-counting","tag-easy","tag-string","tag-vowel","entry","simple"],"_links":{"self":[{"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/posts\/7856","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/comments?post=7856"}],"version-history":[{"count":3,"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/posts\/7856\/revisions"}],"predecessor-version":[{"id":7859,"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/posts\/7856\/revisions\/7859"}],"wp:attachment":[{"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/media?parent=7856"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/categories?post=7856"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/zxi.mytechroad.com\/blog\/wp-json\/wp\/v2\/tags?post=7856"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}