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Posts published in “Hashtable”

花花酱 LeetCode 1233. Remove Sub-Folders from the Filesystem

Given a list of folders, remove all sub-folders in those folders and return in any order the folders after removing.

If a folder[i] is located within another folder[j], it is called a sub-folder of it.

The format of a path is one or more concatenated strings of the form: / followed by one or more lowercase English letters. For example, /leetcode and /leetcode/problems are valid paths while an empty string and / are not.

Example 1:

Input: folder = ["/a","/a/b","/c/d","/c/d/e","/c/f"]
Output: ["/a","/c/d","/c/f"]
Explanation: Folders "/a/b/" is a subfolder of "/a" and "/c/d/e" is inside of folder "/c/d" in our filesystem.

Example 2:

Input: folder = ["/a","/a/b/c","/a/b/d"]
Output: ["/a"]
Explanation: Folders "/a/b/c" and "/a/b/d/" will be removed because they are subfolders of "/a".

Example 3:

Input: folder = ["/a/b/c","/a/b/ca","/a/b/d"]
Output: ["/a/b/c","/a/b/ca","/a/b/d"]

Constraints:

  • 1 <= folder.length <= 4 * 10^4
  • 2 <= folder[i].length <= 100
  • folder[i] contains only lowercase letters and ‘/’
  • folder[i] always starts with character ‘/’
  • Each folder name is unique.

Solution: HashTable

Time complexity: O(n*L)
Space complexity: O(n*L)

C++

花花酱 LeetCode 49. Group Anagrams

Given an array of strings, group anagrams together.

Example:

Input: ["eat", "tea", "tan", "ate", "nat", "bat"],
Output:
[
  ["ate","eat","tea"],
  ["nat","tan"],
  ["bat"]
]

Note:

  • All inputs will be in lowercase.
  • The order of your output does not matter.

Solution: HashTable

The sorted word will be the key of each group

Time complexity: O(sum(l*log(l)))
Space complexity: O(sum(l))

C++

花花酱 LeeCode 1207. Unique Number of Occurrences

Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is unique.

Example 1:

Input: arr = [1,2,2,1,1,3]
Output: true
Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences.

Example 2:

Input: arr = [1,2]
Output: false

Example 3:

Input: arr = [-3,0,1,-3,1,1,1,-3,10,0]
Output: true

Constraints:

  • 1 <= arr.length <= 1000
  • -1000 <= arr[i] <= 1000

Solution: HashTable

Time complexity: O(n)
Space complexity: O(n)

C++

花花酱 LeetCode 1189. Maximum Number of Balloons

Given a string text, you want to use the characters of text to form as many instances of the word “balloon” as possible.

You can use each character in text at most once. Return the maximum number of instances that can be formed.

Example 1:

Input: text = "nlaebolko"
Output: 1

Example 2:

Input: text = "loonbalxballpoon"
Output: 2

Example 3:

Input: text = "leetcode"
Output: 0

Constraints:

  • 1 <= text.length <= 10^4
  • text consists of lower case English letters only.

Solution: HashTable

Use a hashtable to count the occurrence of each letter and find the bottleneck one.

Time complexity: O(n)
Space complexity: O(1)

C++

花花酱 LeetCode 1178. Number of Valid Words for Each Puzzle

With respect to a given puzzle string, a word is valid if both the following conditions are satisfied:

  • word contains the first letter of puzzle.
  • For each letter in word, that letter is in puzzle.
    For example, if the puzzle is “abcdefg”, then valid words are “faced”, “cabbage”, and “baggage”; while invalid words are “beefed” (doesn’t include “a”) and “based” (includes “s” which isn’t in the puzzle).

Return an array answer, where answer[i] is the number of words in the given word list words that are valid with respect to the puzzle puzzles[i].

Example :

Input: 
words = ["aaaa","asas","able","ability","actt","actor","access"], 
puzzles = ["aboveyz","abrodyz","abslute","absoryz","actresz","gaswxyz"]
Output: [1,1,3,2,4,0]
Explanation:
1 valid word for "aboveyz" : "aaaa" 
1 valid word for "abrodyz" : "aaaa"
3 valid words for "abslute" : "aaaa", "asas", "able"
2 valid words for "absoryz" : "aaaa", "asas"
4 valid words for "actresz" : "aaaa", "asas", "actt", "access"
There're no valid words for "gaswxyz" cause none of the words in the list contains letter 'g'.

Constraints:

  • 1 <= words.length <= 10^5
  • 4 <= words[i].length <= 50
  • 1 <= puzzles.length <= 10^4
  • puzzles[i].length == 7
  • words[i][j]puzzles[i][j] are English lowercase letters.
  • Each puzzles[i] doesn’t contain repeated characters.

Solution: Subsets

Preprocessing:
Compress each word to a bit map, and compute the frequency of each bit map.
Since there are at most |words| bitmaps while its value ranging from 0 to 2^26, thus it’s better to use a hashtable instead of an array.

Query:
Use the same way to compress a puzzle into a bit map.
Try all subsets (at most 128) of the puzzle (the bit of the first character is be must), and check how many words match each subset.

words = [“aaaa”,”asas”,”able”,”ability”,”actt”,”actor”,”access”],
puzzle = “abslute”
bitmap(“aaaa”) = {0}
bitmap(“asas”) = {0, 18}
bitmap(“able”) = {0,1,4,11}
bitmap(“actt”) = {0, 2, 19}
bitmap(“actor”) = {0, 2, 14, 17, 19}
bitmap(“access”) = {0, 2, 4, 18}

bitmap(“abslute”) = {0, 1, 4, 11, 18, 19, 20}

Time complexity: O(sum(len(w_i)) + |puzzles|)
Space complexity: O(|words|)

C++