Problem
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.
You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.
Example 1:
Input: ["Shogun", "Tapioca Express", "Burger King", "KFC"] ["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"] Output: ["Shogun"] Explanation: The only restaurant they both like is "Shogun".
Example 2:
Input: ["Shogun", "Tapioca Express", "Burger King", "KFC"] ["KFC", "Shogun", "Burger King"] Output: ["Shogun"] Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).
Note:
- The length of both lists will be in the range of [1, 1000].
- The length of strings in both lists will be in the range of [1, 30].
- The index is starting from 0 to the list length minus 1.
- No duplicates in both lists.
Solution
Time complexity: O(n+m)
Space complexity: O(n)
C++
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// Author: Huahua // Running time: 103 ms class Solution { public: vector<string> findRestaurant(vector<string>& list1, vector<string>& list2) { unordered_map<string, int> indices; for (int i = 0; i < list1.size(); ++i) indices[list1[i]] = i; vector<string> ans; int best_index = INT_MAX; string best; for (int i = 0; i < list2.size(); ++i) { if (!indices.count(list2[i])) continue; int index = indices[list2[i]] + i; if (index < best_index) ans.clear(); if (index <= best_index) { best_index = index; ans.push_back(list2[i]); } } return ans; } }; |
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