题目大意：给你一些用字母表示的任务，执行每个任务需要单位时间的CPU。对于相同的任务，CPU需要n个单位时间的冷却时间，期间可以执行其他不相同的任务。问最少多少时间可以完成所有任务。
Given a char array representing tasks CPU need to do. It contains capital letters A to Z where different letters represent different tasks.Tasks could be done without original order. Each task could be done in one interval. For each interval, CPU could finish one task or just be idle.
However, there is a non-negative cooling interval n that means between two same tasks, there must be at least n intervals that CPU are doing different tasks or just be idle.
You need to return the least number of intervals the CPU will take to finish all the given tasks.
Example 1:
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Input: tasks = ["A","A","A","B","B","B"], n = 2 Output: 8 Explanation: A -> B -> idle -> A -> B -> idle -> A -> B. |
Note:
- The number of tasks is in the range [1, 10000].
- The integer n is in the range [0, 100].
Idea:
Counting
Time complexity: O(n)
Space complexity: O(1)
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// Author: Huahua // Runtime: 56 ms class Solution { public: int leastInterval(vector<char>& tasks, int n) { vector<int> count(26, 0); for (const char task : tasks) ++count[task - 'A']; const int max_count = *max_element(count.begin(), count.end()); size_t ans = (max_count - 1) * (n + 1); ans += count_if(count.begin(), count.end(), [max_count](int c){ return c == max_count; }); return max(tasks.size(), ans); } }; |