Press "Enter" to skip to content

Posts tagged as “tail”

花花酱 LeetCode 1669. Merge In Between Linked Lists

You are given two linked lists: list1 and list2 of sizes n and m respectively.

Remove list1‘s nodes from the ath node to the bth node, and put list2 in their place.

The blue edges and nodes in the following figure incidate the result:

Build the result list and return its head.

Example 1:

Input: list1 = [0,1,2,3,4,5], a = 3, b = 4, list2 = [1000000,1000001,1000002]
Output: [0,1,2,1000000,1000001,1000002,5]
Explanation: We remove the nodes 3 and 4 and put the entire list2 in their place. The blue edges and nodes in the above figure indicate the result.

Example 2:

Input: list1 = [0,1,2,3,4,5,6], a = 2, b = 5, list2 = [1000000,1000001,1000002,1000003,1000004]
Output: [0,1,1000000,1000001,1000002,1000003,1000004,6]
Explanation: The blue edges and nodes in the above figure indicate the result.

Constraints:

  • 3 <= list1.length <= 104
  • 1 <= a <= b < list1.length - 1
  • 1 <= list2.length <= 104

Solution: List Operations

Find the following nodes:
1. previous node to the a-th node: prev_a
2. the b-th node: node_b
3. tail node of list2: tail2

prev_a->next = list2
tail2->next = node_b

return list1

Time complexity: O(m+n)
Space complexity: O(1)

C++