You are given a 2D integer array ranges and two integers left and right. Each ranges[i] = [starti, endi] represents an inclusive interval between starti and endi.
Return true if each integer in the inclusive range [left, right] is covered by at least one interval in ranges. Return false otherwise.
An integer x is covered by an interval ranges[i] = [starti, endi] if starti <= x <= endi.
Example 1:
Input: ranges = [[1,2],[3,4],[5,6]], left = 2, right = 5 Output: true Explanation: Every integer between 2 and 5 is covered: - 2 is covered by the first range. - 3 and 4 are covered by the second range. - 5 is covered by the third range.
Example 2:
Input: ranges = [[1,10],[10,20]], left = 21, right = 21 Output: false Explanation: 21 is not covered by any range.
Constraints:
1 <= ranges.length <= 501 <= starti <= endi <= 501 <= left <= right <= 50
Solution 1: Hashtable
Time complexity: O(n * (right – left))
Space complexity: O(right – left)
C++
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// Author: Huahua class Solution { public: bool isCovered(vector<vector<int>>& ranges, int left, int right) { unordered_set<int> s; for (const auto& range : ranges) for (int i = max(left, range[0]); i <= min(right, range[1]); ++i) s.insert(i); return s.size() == right - left + 1; } }; |
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