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花花酱 LeetCode 891. Sum of Subsequence Widths

Problem

Given an array of integers A, consider all non-empty subsequences of A.

For any sequence S, let the width of S be the difference between the maximum and minimum element of S.

Return the sum of the widths of all subsequences of A.

As the answer may be very large, return the answer modulo 10^9 + 7.

Example 1:

Input: [2,1,3]
Output: 6
Explanation:
Subsequences are [1], [2], [3], [2,1], [2,3], [1,3], [2,1,3].
The corresponding widths are 0, 0, 0, 1, 1, 2, 2.
The sum of these widths is 6.

Note:

  • 1 <= A.length <= 20000
  • 1 <= A[i] <= 20000

 

Solution: Math

Sort the array, for A[i]:

  • i numbers <= A[i]. A[i] is the upper bound of 2^i subsequences.
  • n – i – 1 numbers >= A[i]. A[i] is the lower bound of 2^(n – i – 1) subsequences.
  • A[i] contributes A[i] * 2^i – A[i] * 2^(n – i – 1) to the ans.
\(ans = \sum\limits_{i=0}^{n-1}A_{i}2^{i} – A_{i}2^{n – i – 1} =\sum\limits_{i=0}^{n-1}(A_i – A_{n-i-1})2^{i}\)

Time complexity: O(nlogn)

Space complexity: O(1)

Time complexity: O(n)

Space complexity: O(n)

Counting sort

 

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