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花花酱 LeetCode 746. Min Cost Climbing Stairs

Problem:

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed).

Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step with index 0, or the step with index 1.

Example 1:

Example 2:

Note:

  1. cost will have a length in the range [2, 1000].
  2. Every cost[i] will be an integer in the range [0, 999].

题目大意:

有一个楼梯,要离开i层需要付cost[i]的费用,每次可以爬1层或2层。问你最少花多少钱能够达到顶楼。

Solution:

C++ / Recursion + Memorization 记忆化递归

 

C++ / DP 动态规划

O(1) Space

 

花花酱 LeetCode 377. Combination Sum IV

Problem:

Given an integer array with all positive numbers and no duplicates, find the number of possible combinations that add up to a positive integer target.

Example:

题目大意:给你一些数和一个目标值,问使用这些数(每个数可以被使用任意次数)加起来等于目标值的组合(其实是不重复的排列)有多少种。

Idea:

DP

Solution:

C++ / Recursion + Memorization

 

C++ / DP

Related Problems:

花花酱 LeetCode 540. Single Element in a Sorted Array

Problem:

Given a sorted array consisting of only integers where every element appears twice except for one element which appears once. Find this single element that appears only once.

Example 1:

Example 2:

Note: Your solution should run in O(log n) time and O(1) space.

Idea:

Binary search.

Time complexity: O(logn)

Space complexity: O(1)

Solution: 

C++

 

花花酱 LeetCode 477. Total Hamming Distance

Problem:

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Now your job is to find the total Hamming distance between all pairs of the given numbers.

Example:

Note:

  1. Elements of the given array are in the range of to 10^9
  2. Length of the array will not exceed 10^4.

题目大意:给你一堆数,让你求所有数对的HammingDistance的总和。

Idea:

  1. Brute force, compute HammingDistance for all pairs. O(n^2) TLE
  2. Count how many ones on i-th bit, assuming k. Distance += k * (n – k). O(n)

Solution:

C++ / O(n)

 

花花酱 LeetCode 210. Course Schedule II

Problem

There are a total of n courses you have to take, labeled from 0 to n - 1.

Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]

Given the total number of courses and a list of prerequisite pairs, return the ordering of courses you should take to finish all courses.

There may be multiple correct orders, you just need to return one of them. If it is impossible to finish all courses, return an empty array.

For example:

There are a total of 2 courses to take. To take course 1 you should have finished course 0. So the correct course order is [0,1]

There are a total of 4 courses to take. To take course 3 you should have finished both courses 1 and 2. Both courses 1 and 2 should be taken after you finished course 0. So one correct course order is [0,1,2,3]. Another correct ordering is[0,2,1,3].

Note:

  1. The input prerequisites is a graph represented by a list of edges, not adjacency matrices. Read more about how a graph is represented.
  2. You may assume that there are no duplicate edges in the input prerequisites.

题目大意:

给你一些课程和它的先修课程,让你输出修课顺序。如果无法修完所有课程,返回空数组。


Idea

Topological sorting

拓扑排序

Solution 1: Topological Sorting

Time complexity: O(V+E)

Space complexity: O(V+E)

C++

Java

Related Problems: