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花花酱 LeetCode 82. Remove Duplicates from Sorted List II

By zxi on September 30, 2019

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

Example 1:

Input: 1->2->3->3->4->4->5
Output: 1->2->5

Example 2:

Input: 1->1->1->2->3
Output: 2->3

Solution:

Time complexity: O(n)
Space complexity: O(1)

C++

Related Problems

花花酱 LeetCode 83. Remove Duplicates from Sorted List

By zxi on September 30, 2019

Given a sorted linked list, delete all duplicates such that each element appear only once.

Example 1:

Input: 1->1->2
Output: 1->2

Example 2:

Input: 1->1->2->3->3
Output: 1->2->3

Solution:

Time complexity: O(n)
Space complexity: O(1)

C++

花花酱 LeetCode 86. Partition List

By zxi on September 30, 2019

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.

You should preserve the original relative order of the nodes in each of the two partitions.

Example:

Input: head = 1->4->3->2->5->2, x = 3
Output: 1->2->2->4->3->5

Solution: Two dummy heads

Time complexity: O(n)
Space complexity: O(1)

C++

花花酱 LeetCode 93. Restore IP Addresses

By zxi on September 30, 2019

Given a string containing only digits, restore it by returning all possible valid IP address combinations.

Example:

Input: "25525511135"
Output: ["255.255.11.135", "255.255.111.35"]

Solution: DFS

The range of valid numbers is [0, 255]

Time complexity: O(3^4)
Space complexity: O(1)

C++

花花酱 LeetCode 58. Length of Last Word

By zxi on September 30, 2019

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World"
Output: 5

Solution:

There can be tailing spaces, e.g. “abc “, we need to trim the string first and then scan the string in reverse order until a space or reach the beginning of the string.

Time complexity: O(n)
Space complexity: O(1)

C++