You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.
Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.
Return true if a and b are alike. Otherwise, return false.
Example 1:
Input: s = "book" Output: true Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.
Example 2:
Input: s = "textbook" Output: false Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike. Notice that the vowel o is counted twice.
Example 3:
Input: s = "MerryChristmas" Output: false
Example 4:
Input: s = "AbCdEfGh" Output: true
Constraints:
2 <= s.length <= 1000s.lengthis even.sconsists of uppercase and lowercase letters.
Solution: Counting
Time complexity: O(n)
Space complexity: O(1)
Python3
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# Author: Huahua class Solution: def halvesAreAlike(self, s: str) -> bool: def count(s: str) -> int: return sum(c in 'aeiouAEIOU' for c in s) n = len(s) return count(s[:n//2]) == count(s[n//2:]) |
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