You are given the head of a linked list, and an integer k.
Return the head of the linked list after swapping the values of the kth node from the beginning and the kth node from the end (the list is 1-indexed).
Example 1:

Input: head = [1,2,3,4,5], k = 2 Output: [1,4,3,2,5]
Example 2:
Input: head = [7,9,6,6,7,8,3,0,9,5], k = 5 Output: [7,9,6,6,8,7,3,0,9,5]
Example 3:
Input: head = [1], k = 1 Output: [1]
Example 4:
Input: head = [1,2], k = 1 Output: [2,1]
Example 5:
Input: head = [1,2,3], k = 2 Output: [1,2,3]
Constraints:
- The number of nodes in the list is
n. 1 <= k <= n <= 1050 <= Node.val <= 100
Solution:
Two passes. First pass, find the length of the list. Second pass, record the k-th and n-k+1-th node.
Once done swap their values.
Time complexity: O(n)
Space complexity: O(1)
C++
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class Solution { public: ListNode* swapNodes(ListNode* head, int k) { int l = 0; ListNode* cur = head; while (cur) { cur = cur->next; ++l; } cur = head; ListNode* n1 = nullptr; ListNode* n2 = nullptr; for (int i = 1; i <= l; ++i, cur = cur->next) { if (i == k) n1 = cur; if (i == l - k + 1) n2 = cur; } swap(n1->val, n2->val); return head; } }; |
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