Problem
https://leetcode.com/problems/range-addition-ii/description/
Given an m * n matrix M initialized with all 0‘s and several update operations.
Operations are represented by a 2D array, and each operation is represented by an array with two positiveintegers a and b, which means M[i][j] should be added by one for all 0 <= i < a and 0 <= j < b.
You need to count and return the number of maximum integers in the matrix after performing all the operations.
Example 1:
Input: m = 3, n = 3 operations = [[2,2],[3,3]] Output: 4 Explanation: Initially, M = [[0, 0, 0], [0, 0, 0], [0, 0, 0]] After performing [2,2], M = [[1, 1, 0], [1, 1, 0], [0, 0, 0]] After performing [3,3], M = [[2, 2, 1], [2, 2, 1], [1, 1, 1]] So the maximum integer in M is 2, and there are four of it in M. So return 4.
Note:
- The range of m and n is [1,40000].
- The range of a is [1,m], and the range of b is [1,n].
- The range of operations size won’t exceed 10,000.
Solution:
Time Complexity: O(n)
Space Complexity: O(1)
C++
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// Author: Huahua // Running time: 9 ms class Solution { public: int maxCount(int m, int n, vector<vector<int>>& ops) { for (const auto& range : ops) { m = min(m, range[0]); n = min(n, range[1]); } return m * n; } }; |
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