You are given an integer n indicating the number of people in a network. Each person is labeled from 0 to n - 1.

You are also given a 0-indexed 2D integer array restrictions, where restrictions[i] = [xi, yi] means that person xi and person yi cannot become friends,either directly or indirectly through other people.

Initially, no one is friends with each other. You are given a list of friend requests as a 0-indexed 2D integer array requests, where requests[j] = [uj, vj] is a friend request between person uj and person vj.

A friend request is successful if uj and vj can be friends. Each friend request is processed in the given order (i.e., requests[j] occurs before requests[j + 1]), and upon a successful request, uj and vj become direct friends for all future friend requests.

Return boolean array result, where each result[j] is true if the jth friend request is successful or false if it is not.

Note: If uj and vj are already direct friends, the request is still successful.

Example 1:

Input: n = 3, restrictions = [[0,1]], requests = [[0,2],[2,1]]
Output: [true,false]
Explanation:
Request 0: Person 0 and person 2 can be friends, so they become direct friends.
Request 1: Person 2 and person 1 cannot be friends since person 0 and person 1 would be indirect friends (1--2--0).


Example 2:

Input: n = 3, restrictions = [[0,1]], requests = [[1,2],[0,2]]
Output: [true,false]
Explanation:
Request 0: Person 1 and person 2 can be friends, so they become direct friends.
Request 1: Person 0 and person 2 cannot be friends since person 0 and person 1 would be indirect friends (0--2--1).


Example 3:

Input: n = 5, restrictions = [[0,1],[1,2],[2,3]], requests = [[0,4],[1,2],[3,1],[3,4]]
Output: [true,false,true,false]
Explanation:
Request 0: Person 0 and person 4 can be friends, so they become direct friends.
Request 1: Person 1 and person 2 cannot be friends since they are directly restricted.
Request 2: Person 3 and person 1 can be friends, so they become direct friends.
Request 3: Person 3 and person 4 cannot be friends since person 0 and person 1 would be indirect friends (0--4--3--1).


Constraints:

• 2 <= n <= 1000
• 0 <= restrictions.length <= 1000
• restrictions[i].length == 2
• 0 <= xi, yi <= n - 1
• xi != yi
• 1 <= requests.length <= 1000
• requests[j].length == 2
• 0 <= uj, vj <= n - 1
• uj != vj

Solution: Union Find / Brute Force

For each request, check all restrictions.

Time complexity: O(req * res)
Space complexity: O(n)

## C++

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