Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
Implement the MinStack
class:
MinStack()
initializes the stack object.void push(int val)
pushes the elementval
onto the stack.void pop()
removes the element on the top of the stack.int top()
gets the top element of the stack.int getMin()
retrieves the minimum element in the stack.
Example 1:
Input ["MinStack","push","push","push","getMin","pop","top","getMin"] [[],[-2],[0],[-3],[],[],[],[]] Output
[null,null,null,null,-3,null,0,-2]
Explanation MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); // return -3 minStack.pop(); minStack.top(); // return 0 minStack.getMin(); // return -2
Constraints:
-231 <= val <= 231 - 1
- Methods
pop
,top
andgetMin
operations will always be called on non-empty stacks. - At most
3 * 104
calls will be made topush
,pop
,top
, andgetMin
.
Solution 1: Two Stacks
One normal stack, one monotonic stack to store the min values.
Time complexity: O(1) per op
Space complexity: O(n)
C++
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// Author: Huahua class MinStack { public: void push(int x) { m_data.push(x); if (m_s.empty() || x <= m_s.top()) m_s.push(x); } void pop() { if (!m_s.empty() && m_data.top() == m_s.top()) m_s.pop(); m_data.pop(); } int top() { return m_data.top(); } int getMin() { return m_s.empty() ? m_data.top() : m_s.top(); } private: stack<int> m_data; stack<int> m_s; }; |
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