Problem
We have a string S
of lowercase letters, and an integer array shifts
.
Call the shift of a letter, the next letter in the alphabet, (wrapping around so that 'z'
becomes 'a'
).
For example, shift('a') = 'b'
, shift('t') = 'u'
, and shift('z') = 'a'
.
Now for each shifts[i] = x
, we want to shift the first i+1
letters of S
, x
times.
Return the final string after all such shifts to S
are applied.
Example 1:
Input: S = "abc", shifts = [3,5,9] Output: "rpl" Explanation: We start with "abc". After shifting the first 1 letters of S by 3, we have "dbc". After shifting the first 2 letters of S by 5, we have "igc". After shifting the first 3 letters of S by 9, we have "rpl", the answer.
Note:
1 <= S.length = shifts.length <= 20000
0 <= shifts[i] <= 10 ^ 9
Solution
Time complexity: O(n)
Space complexity: O(1)
C++
1 2 3 4 5 6 7 8 9 10 11 12 13 |
// Author: Huahua // Running time: 54 ms class Solution { public: string shiftingLetters(string S, vector<int>& shifts) { int c = 0; for (int i = shifts.size() - 1; i >= 0; --i) { c += (shifts[i] % 26); S[i] = (S[i] - 'a' + c) % 26 + 'a'; } return S; } }; |
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