Given an array of integers arr
, and three integers a
, b
and c
. You need to find the number of good triplets.
A triplet (arr[i], arr[j], arr[k])
is good if the following conditions are true:
0 <= i < j < k < arr.length
|arr[i] - arr[j]| <= a
|arr[j] - arr[k]| <= b
|arr[i] - arr[k]| <= c
Where |x|
denotes the absolute value of x
.
Return the number of good triplets.
Example 1:
Input: arr = [3,0,1,1,9,7], a = 7, b = 2, c = 3 Output: 4 Explanation: There are 4 good triplets: [(3,0,1), (3,0,1), (3,1,1), (0,1,1)].
Example 2:
Input: arr = [1,1,2,2,3], a = 0, b = 0, c = 1 Output: 0 Explanation: No triplet satisfies all conditions.
Constraints:
3 <= arr.length <= 100
0 <= arr[i] <= 1000
0 <= a, b, c <= 1000
Solution: Brute Force
Time complexity: O(n^3)
Space complexity: O(1)
C++
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 |
// Author: Huahua class Solution { public: int countGoodTriplets(vector<int>& arr, int a, int b, int c) { const int n = arr.size(); int ans = 0; for (int i = 0; i < n; ++i) for (int j = i + 1; j < n; ++j) for (int k = j + 1; k < n; ++k) if (abs(arr[i] - arr[j]) <= a && abs(arr[j] - arr[k]) <= b && abs(arr[i] - arr[k]) <= c) ++ans; return ans; } }; |
请尊重作者的劳动成果,转载请注明出处!花花保留对文章/视频的所有权利。
如果您喜欢这篇文章/视频,欢迎您捐赠花花。
If you like my articles / videos, donations are welcome.
Be First to Comment