Given an integer array arr, return true if there are three consecutive odd numbers in the array. Otherwise, return false.
Example 1:
Input: arr = [2,6,4,1] Output: false Explanation: There are no three consecutive odds.
Example 2:
Input: arr = [1,2,34,3,4,5,7,23,12] Output: true Explanation: [5,7,23] are three consecutive odds.
Constraints:
1 <= arr.length <= 10001 <= arr[i] <= 1000
Solution: Counting
Time complexity: O(n)
Space complexity: O(1)
C++
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class Solution { public: bool threeConsecutiveOdds(vector<int>& arr) { int count = 0; for (int x : arr) { if (x & 1) { if (++count == 3) return true; } else { count = 0; } } return false; } }; |
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