Problem
In a row of seats, 1 represents a person sitting in that seat, and 0 represents that the seat is empty.
There is at least one empty seat, and at least one person sitting.
Alex wants to sit in the seat such that the distance between him and the closest person to him is maximized.
Return that maximum distance to closest person.
Example 1:
Input: [1,0,0,0,1,0,1] Output: 2 Explanation: If Alex sits in the second open seat (seats[2]), then the closest person has distance 2. If Alex sits in any other open seat, the closest person has distance 1. Thus, the maximum distance to the closest person is 2.
Example 2:
Input: [1,0,0,0] Output: 3 Explanation: If Alex sits in the last seat, the closest person is 3 seats away. This is the maximum distance possible, so the answer is 3.
Note:
1 <= seats.length <= 20000seatscontains only 0s or 1s, at least one0, and at least one1.
Solution
Time complexity: O(n)
Space complexity: O(1)
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 |
// Author: Huahua // Running time: 15 ms class Solution { public: int maxDistToClosest(vector<int>& seats) { int n = seats.size(); int prev = -1; int ans = 0; for (int i = 0; i <= n; ++i) { if (i == n) ans = max(ans, n - prev - 1); else if (seats[i]) { if (prev == -1) ans = i; else ans = max(ans, (i - prev) / 2); prev = i; } } return ans; } }; |
请尊重作者的劳动成果，转载请注明出处！花花保留对文章／视频的所有权利。
如果您喜欢这篇文章／视频，欢迎您捐赠花花。
If you like my articles / videos, donations are welcome.
Paypal
Venmo
huahualeetcode
huahualeetcode
微信打赏
Be First to Comment