Problem

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.

Example:

Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6],       n = 3

Output: [1,2,2,3,5,6]

Solution:

Fill nums1 from back to front

Time complexity: O(m + n)

Space complexity: O(1) in-place

// Author: Huahua

class Solution {

public:

void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {

int i = m - 1;

int j = n - 1;

int tail = m + n - 1;

while (j >= 0)

nums1[tail--] = (i >= 0 && nums1[i] > nums2[j]) ? nums1[i--] : nums2[j--];

}

};

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